1-1.6x^2=0

Solution for 1-1.6x^2=0 equation:

1-1.6x^2=0

a = -1.6; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-1.6)·1
Δ = 6.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{6.4}}{2*-1.6}=\frac{0-\sqrt{6.4}}{-3.2}
=-\frac{\sqrt{}}{-3.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{6.4}}{2*-1.6}=\frac{0+\sqrt{6.4}}{-3.2}
=\frac{\sqrt{}}{-3.2}
$